Evaluate using suitable identities : $(104)^{3}$
$1124864$
$1088844$
$1126866$
$1224844$
We have
$(104)^{3}=(100+4)^{3}$
$=(100)^{3}+(4)^{3}+3(100)(4)(100+4)$
(Using Identity $VI$)
$=1000000+64+124800$
$=1124864$
Give one example each of a binomial of degree $35 $, and of a monomial of degree $100 $.
Evaluate $105 \times 106$ without multiplying directly.
Divide $p(x)$ by $g(x)$, where $p(x) = x + 3x^2 -1$ and $g(x) = 1 + x$.
Find the value of $k$, if $x -1$ is a factor of $p(x)$ in this case : $p(x)=k x^{2}-\sqrt{2} x+1$
Find the remainder when $x^4+x^3-2x^2+x+1$ is divided by $x -1$.
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